What is the solution for (dy)/(dt)=(-csc(t)cot(t))e^{-csc(t)} ?

The solution for (dy)/(dt)=(-csc(t)cot(t))e^{-csc(t)} is y=-e^{-csc(t)}+c_{1}

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(dy)/(dt)=(-csc(t)cot(t))e^{-csc(t)}

\frac{d y}{d t} = (- csc (t) cot (t)) e^{- c s c (t)}

y = - e^{- c s c (t)} + c_{1}

Solution steps

\frac{d y}{d t} = (- csc (t) cot (t)) e^{- c s c (t)}

Substitute

\frac{d y}{d t}

with

y^{'} (t)

y^{^{'}} (t) = (- csc (t) cot (t)) e^{- c s c (t)}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (- csc (t) cot (t)) e^{- c s c (t)} d t

\int (- csc (t) cot (t)) e^{- c s c (t)} d t = - e^{- c s c (t)} + c_{1}

y = - e^{- c s c (t)} + c_{1}

x \to \infty lim (- 3 x^{3})

x \to 0 - lim (1 - x^{2})

x \to 0 lim ((1 - 4 x)^{\frac{7}{x}})

n = 1 \sum \infty \frac{35}{- 6 ^{n}}

\int sin (\frac{θ}{2}) d θ

What is the solution for (dy)/(dt)=(-csc(t)cot(t))e^{-csc(t)} ?
The solution for (dy)/(dt)=(-csc(t)cot(t))e^{-csc(t)} is y=-e^{-csc(t)}+c_{1}