What is the derivative of f(x)=4x^3-8x ?

The derivative of f(x)=4x^3-8x is 12x^2-8

What is the first derivative of f(x)=4x^3-8x ?

The first derivative of f(x)=4x^3-8x is 12x^2-8

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derivative of

f (x) = 4 x^{3} - 8 x

12 x^{2} - 8

Solution steps

\frac{d}{d x} (4 x^{3} - 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (8 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (8 x) = 8

= 12 x^{2} - 8

a e^{b t}

f (x) = \frac{3}{x + 2}, at x = 3

sin (9 x) + cos (2 x)

\int \frac{1 - z}{- 1 - z}

(ln (x))^{^{'}}

What is the derivative of f(x)=4x^3-8x ?
The derivative of f(x)=4x^3-8x is 12x^2-8
What is the first derivative of f(x)=4x^3-8x ?
The first derivative of f(x)=4x^3-8x is 12x^2-8