What is (\partial)/(\partial y)(x^2yz^3) ?

The answer to (\partial)/(\partial y)(x^2yz^3) is x^2z^3

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(\partial)/(\partial y)(x^2yz^3)

\frac{\partial}{\partial y} (x^{2} y z^{3})

x^{2} z^{3}

Solution steps

\frac{\partial}{\partial y} (x^{2} y z^{3})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} z^{3} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x^{2} z^{3} \cdot 1

Simplify

= x^{2} z^{3}

f (x) = 1 - 4 x

\frac{d}{d x} (\frac{4}{( 1 + 2 x ) ^{2}})

\frac{d}{d x} (ln (17 x))

x \to - 5 lim (3 x - ∣ x + 5 ∣)

y = \frac{1}{x - 2}, at x = 5

What is (\partial)/(\partial y)(x^2yz^3) ?
The answer to (\partial)/(\partial y)(x^2yz^3) is x^2z^3