What is the integral from x to 3 of sin(t^2) ?

The integral from x to 3 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*3)-sqrt(pi/2)\S(sqrt(2/pi)x)

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integral from x to 3 of sin(t^2)

\int_{x}^{3} sin (t^{2}) d t

\frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (\frac{2}{π} x)

Solution steps

\int_{x}^{3} sin (t^{2}) d t

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} t)]_{x}^{3}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (\frac{2}{π} x)

= \frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (\frac{2}{π} x)

\frac{d}{d x} (\frac{50}{x ^{7}})

\frac{d y}{d x} (x 16 - x) = 0

4 e^{- 7 t} cos (9 t)

\int_{- \infty}^{0} \frac{1}{2 - 9 x} d x

What is the integral from x to 3 of sin(t^2) ?
The integral from x to 3 of sin(t^2) is sqrt(pi/2)\S(sqrt(2/pi)*3)-sqrt(pi/2)\S(sqrt(2/pi)x)