What is the sum from n=0 to infinity of 3(-0.1)^n ?

The sum from n=0 to infinity of 3(-0.1)^n is 2.72727…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of 3(-0.1)^n

n = 0 \sum \infty 3 (- 0.1)^{n}

2.72727 \dots

Solution steps

n = 0 \sum \infty 3 (- 0.1)^{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 3 \cdot n = 0 \sum \infty (- 0.1)^{n}

Apply Series Geometric Test:

0.90909 \dots

= 3 \cdot 0.90909 \dots

Simplify

= 2.72727 \dots

\int arctan (u) d u

\int_{- 4}^{4} 4 (16 - x^{2}) d x

2 x^{3} - 5

x \to - 1 - lim (\frac{1}{x - 1} + e^{x})

\frac{d}{d t} (3 t)

What is the sum from n=0 to infinity of 3(-0.1)^n ?
The sum from n=0 to infinity of 3(-0.1)^n is 2.72727…