What is the derivative of sin(4x^2) ?

The derivative of sin(4x^2) is cos(4x^2)*8x

What is the first derivative of sin(4x^2) ?

The first derivative of sin(4x^2) is cos(4x^2)*8x

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derivative of

sin (4 x^{2})

cos (4 x^{2}) \cdot 8 x

Solution steps

\frac{d}{d x} (sin (4 x^{2}))

Apply the chain rule:

cos (4 x^{2}) \frac{d}{d x} (4 x^{2})

= cos (4 x^{2}) \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{2}) = 8 x

= cos (4 x^{2}) \cdot 8 x

d r = e (r sin (θ) d θ - cos (θ) d r)

\int y - \frac{x}{y ^{2}} sin (\frac{x}{y}) d y

\frac{\partial}{\partial y} (1 + x^{4} + y^{3})

\int (3 x + 2)^{\frac{3}{2}} d x

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{\frac{1}{2}})

What is the derivative of sin(4x^2) ?
The derivative of sin(4x^2) is cos(4x^2)*8x
What is the first derivative of sin(4x^2) ?
The first derivative of sin(4x^2) is cos(4x^2)*8x