What is the derivative of (ln(2x)/(2x)) ?

The derivative of (ln(2x)/(2x)) is (1-ln(2x))/(2x^2)

What is the first derivative of (ln(2x)/(2x)) ?

The first derivative of (ln(2x)/(2x)) is (1-ln(2x))/(2x^2)

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\frac{d}{d x} (\frac{ln ( 2 x )}{2 x})

\frac{1 - ln ( 2 x )}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( 2 x )}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{ln ( 2 x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( ln ( 2 x ) ) x - \frac{d x}{d x} ln ( 2 x )}{x ^{2}}

\frac{d}{d x} (ln (2 x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{2} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 2 x )}{x ^{2}}

Simplify

\frac{1}{2} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( 2 x )}{x ^{2}} : \frac{1 - ln ( 2 x )}{2 x ^{2}}

= \frac{1 - ln ( 2 x )}{2 x ^{2}}

\frac{\partial}{\partial u} (u \cdot sin (v))

\int_{- 2}^{1} \frac{1}{2 - x} d x

\frac{d}{d x} (x e^{- 6 x})

tan (e^{5 t}) + e^{t a n (5 t)}

k = 2 \sum \infty \frac{3}{2 ^{k}}

What is the derivative of (ln(2x)/(2x)) ?
The derivative of (ln(2x)/(2x)) is (1-ln(2x))/(2x^2)
What is the first derivative of (ln(2x)/(2x)) ?
The first derivative of (ln(2x)/(2x)) is (1-ln(2x))/(2x^2)