What is the tangent of sqrt(7x-6) ?

The tangent of sqrt(7x-6) is y= 7/(2sqrt(7a_{0)-6)}x+sqrt(7a_{0)-6}-(7a_{0})/(2sqrt(7a_{0)-6)}

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tangent of sqrt(7x-6)

tangent of

7 x - 6

y = \frac{7}{2 7 a _{0} - 6} x + 7 a_{0} - 6 - \frac{7 a _{0}}{2 7 a _{0} - 6}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0} - 6)

Find the slope of

y = 7 x - 6 : \frac{d y}{d x} = \frac{7}{2 7 x - 6}

Compute the slope of

y = 7 x - 6

x = a_{0} : m = \frac{7}{2 7 a _{0} - 6}

Find the line with slope m=

\frac{7}{2 7 a _{0} - 6}

and passing through

(a_{0}, 7 a_{0} - 6) : y = \frac{7}{2 7 a _{0} - 6} x + 7 a_{0} - 6 - \frac{7 a _{0}}{2 7 a _{0} - 6}

y = \frac{7}{2 7 a _{0} - 6} x + 7 a_{0} - 6 - \frac{7 a _{0}}{2 7 a _{0} - 6}

\frac{\partial}{\partial x} (\frac{x y}{z})

\frac{d}{d x} (7 + x sec (x))

\int x e^{- x} d x

\frac{d}{d x} (64 e^{4 x})

\frac{d}{d x} (ccos t + t^{2} sin (t))

What is the tangent of sqrt(7x-6) ?
The tangent of sqrt(7x-6) is y= 7/(2sqrt(7a_{0)-6)}x+sqrt(7a_{0)-6}-(7a_{0})/(2sqrt(7a_{0)-6)}