What is (\partial ^2)/(\partial x^2)(ln(x+2y)) ?

The answer to (\partial ^2)/(\partial x^2)(ln(x+2y)) is -1/((x+2y)^2)

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(\partial ^2)/(\partial x^2)(ln(x+2y))

\frac{\partial ^{2}}{\partial x ^{2}} (ln (x + 2 y))

- \frac{1}{( x + 2 y ) ^{2}}

Solution steps

\frac{\partial ^{2}}{\partial x ^{2}} (ln (x + 2 y))

\frac{\partial}{\partial x} (ln (x + 2 y)) = \frac{1}{x + 2 y}

= \frac{\partial}{\partial x} (\frac{1}{x + 2 y})

\frac{\partial}{\partial x} (\frac{1}{x + 2 y}) = - \frac{1}{( x + 2 y ) ^{2}}

= - \frac{1}{( x + 2 y ) ^{2}}

n = 1 \sum \infty \frac{1}{3 n ^{2} + 2}

\frac{d}{d x} (\frac{2 cos ( x ) - 3}{sin ( x )})

x \to 0 lim (1 - \frac{cos ( 5 x )}{x})

(2.3) (4.3)

\frac{d}{d x} (- 12 x sin (x^{2}) - 8 x^{3} cos (x^{2}))

What is (\partial ^2)/(\partial x^2)(ln(x+2y)) ?
The answer to (\partial ^2)/(\partial x^2)(ln(x+2y)) is -1/((x+2y)^2)