What is the integral from 1 to infinity of 1/(n^2) ?

The integral from 1 to infinity of 1/(n^2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to infinity of 1/(n^2)

\int_{1}^{\infty} \frac{1}{n ^{2}}

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{n ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{n ^{2}} d x = \frac{x}{n ^{2}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{n ^{2}} d x =

diverges

= diverges

x, 2 - x, 0

e^{- t^{2}}

x \to 0 lim (\frac{2 x - 2}{x})

\frac{\partial}{\partial y} (1 + x^{4} + y^{4})

y^{^{''}} + y = 2 x e^{x}

What is the integral from 1 to infinity of 1/(n^2) ?
The integral from 1 to infinity of 1/(n^2) is diverges