en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 4/((x+1)^2)

Solution

\int \frac{4}{( x + 1 ) ^{2}} d x

Solution

- \frac{4}{x + 1} + C

Solution steps

\int \frac{4}{( x + 1 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{( x + 1 ) ^{2}} d x

Apply u-substitution

: \int \frac{1}{u ^{2}} d u

= 4 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

: - \frac{1}{u}

= 4 (- \frac{1}{u})

Substitute back

u = x + 1

= 4 (- \frac{1}{x + 1})

Simplify

4 (- \frac{1}{x + 1}) : - \frac{4}{x + 1}

= - \frac{4}{x + 1}

Add a constant to the solution

= - \frac{4}{x + 1} + C

Popular Examples

derivative of 16sin(2x)

\frac{d}{d x} (16 sin (2 x))

inverse oflaplace 1/(2s^2+4s+3)inverse laplace

\frac{1}{2 s ^{2} + 4 s + 3}

y^'+4y=3sin(e^{4x})

y^{^{'}} + 4 y = 3 sin (e^{4 x})

integral of (sqrt(4x^2-16))/x

\int \frac{4 x ^{2} - 16}{x} d x

derivative of (tan(x)^{-1})

\frac{d}{d x} ((tan (x))^{- 1})

Frequently Asked Questions (FAQ)

What is the integral of 4/((x+1)^2) ?
The integral of 4/((x+1)^2) is -4/(x+1)+C