What is the limit as x approaches 0+of (7x)/(sin(x)) ?

The limit as x approaches 0+of (7x)/(sin(x)) is 7

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limit as x approaches 0+of (7x)/(sin(x))

x \to 0 + lim (\frac{7 x}{sin ( x )})

7

Solution steps

x \to 0 + lim (\frac{7 x}{sin ( x )})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 7 \cdot x \to 0 + lim (\frac{x}{sin ( x )})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{1}{cos ( x )})

= 7 \cdot x \to 0 + lim (\frac{1}{cos ( x )})

Plug in the value

x = 0

= 7 \cdot \frac{1}{cos ( 0 )}

Simplify

7 \cdot \frac{1}{cos ( 0 )} : 7

= 7

f (x) = (x^{4} - 2 x + 8)^{6}, at x = 1

\int e^{x^{2}} 2 x^{3} d x

x \to \infty lim (- 5)

f (t) = arcsin (8 t)

y = (x^{2} + 1)^{3} (x - 1)

What is the limit as x approaches 0+of (7x)/(sin(x)) ?
The limit as x approaches 0+of (7x)/(sin(x)) is 7