What is the derivative of e^{x+1}+1 ?

The derivative of e^{x+1}+1 is e^{x+1}

What is the first derivative of e^{x+1}+1 ?

The first derivative of e^{x+1}+1 is e^{x+1}

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\frac{d}{d x} (e^{x + 1} + 1)

e^{x + 1}

Solution steps

\frac{d}{d x} (e^{x + 1} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x + 1}) + \frac{d}{d x} (1)

\frac{d}{d x} (e^{x + 1}) = e^{x + 1}

\frac{d}{d x} (1) = 0

= e^{x + 1} + 0

Simplify

= e^{x + 1}

y^{^{'}} = 2 x y^{\frac{3}{4}}

f (x) = 8 x^{4} + 9 x

n = 1 \sum \infty cos (πn)

f (x) = e^{5 x}, at x = \frac{1}{5} ln (2)

\frac{\partial}{\partial x} (96 - 5 x^{2} - 3 y^{2})

What is the derivative of e^{x+1}+1 ?
The derivative of e^{x+1}+1 is e^{x+1}
What is the first derivative of e^{x+1}+1 ?
The first derivative of e^{x+1}+1 is e^{x+1}