What is (\partial)/(\partial x)(1/x-2y) ?

The answer to (\partial)/(\partial x)(1/x-2y) is -1/(x^2)

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(\partial)/(\partial x)(1/x-2y)

\frac{\partial}{\partial x} (\frac{1}{x} - 2 y)

- \frac{1}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{1}{x} - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{1}{x}) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

\frac{\partial}{\partial x} (2 y) = 0

= - \frac{1}{x ^{2}} - 0

Simplify

= - \frac{1}{x ^{2}}

f (x) = sin^{2} (2 x)

\int csc^{2} (x co) t^{2} x d x

y = - 3 x^{3} + x^{2} + 10 x, x = - \frac{5}{3}, x = 2

x \to a lim (x + x - 4)

\frac{d}{d x} (x cos (x) + sin (x))

What is (\partial)/(\partial x)(1/x-2y) ?
The answer to (\partial)/(\partial x)(1/x-2y) is -1/(x^2)