What is the integral from 0 to 2pi of x ?

The integral from 0 to 2pi of x is 2pi^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of x

\int_{0}^{2 π} x d x

2 π^{2}

Decimal Notation

19.73920 \dots

Solution steps

\int_{0}^{2 π} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2 π}

= [\frac{x ^{2}}{2}]_{0}^{2 π}

Compute the boundaries:

2 π^{2}

= 2 π^{2}

t + t

\frac{d}{d x} (cos (x^{4}) \cdot 4 x^{3})

\frac{d}{d x} (8 8 x^{2} + 3)

y^{^{'}} = \frac{3 x}{y + x ^{2} y}, y (0) = - 3

\frac{\partial}{\partial z} (\frac{1}{z})

What is the integral from 0 to 2pi of x ?
The integral from 0 to 2pi of x is 2pi^2