What is laplacetransform 1/(e^{jt)} ?

The answer to laplacetransform 1/(e^{jt)} is 1/(s+j)

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laplacetransform 1/(e^{jt)}

laplace transform

\frac{1}{e ^{j t}}

\frac{1}{s + j}

Solution steps

L {\frac{1}{e ^{j t}}}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

\frac{1}{e ^{j t}} : f (t) = 1, a = - j

= L {1} (s + j)

L {1} : \frac{1}{s}

= \frac{1}{( s + j )}

= \frac{1}{s + j}

\frac{d}{d x} (e^{x} (x - 9))

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4 x^{2} + 10, 2 x + 7, - 3, 2

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{2}})

\int - \frac{1}{x - 4} d x

What is laplacetransform 1/(e^{jt)} ?
The answer to laplacetransform 1/(e^{jt)} is 1/(s+j)