What is the derivative of 3x^2+1/(x^2) ?

The derivative of 3x^2+1/(x^2) is 6x-2/(x^3)

What is the first derivative of 3x^2+1/(x^2) ?

The first derivative of 3x^2+1/(x^2) is 6x-2/(x^3)

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\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{2}})

6 x - \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x ^{2}})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

= 6 x - \frac{2}{x ^{3}}

\int - \frac{1}{x - 4} d x

4 x - 32 x, at x = 4

\int_{- 1}^{1} x^{4} d x

n = 1 \sum \infty n^{4} (1 + n^{5})

\int \frac{x ^{3}}{x ^{8} + 25} d x

What is the derivative of 3x^2+1/(x^2) ?
The derivative of 3x^2+1/(x^2) is 6x-2/(x^3)
What is the first derivative of 3x^2+1/(x^2) ?
The first derivative of 3x^2+1/(x^2) is 6x-2/(x^3)