What is the solution for y^'+(2-x/(x-1))y=0 ?

The solution for y^'+(2-x/(x-1))y=0 is y=e^{-x-1+c_{1}}x-e^{-x-1+c_{1}}

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y^'+(2-x/(x-1))y=0

y^{^{'}} + (2 - \frac{x}{x - 1}) y = 0

y = e^{- x - 1 + c_{1}} x - e^{- x - 1 + c_{1}}

Solution steps

y^{'} (x) + (2 - \frac{x}{x - 1}) y = 0

Solve separable ODE:

y = e^{- x - 1 + c_{1}} x - e^{- x - 1 + c_{1}}

y = e^{- x - 1 + c_{1}} x - e^{- x - 1 + c_{1}}

x \to 1 lim (\frac{I n ( x )}{x - 1})

y = 8 e^{x} cos (x), (0, 8)

\frac{\partial}{\partial y} (x^{y^{2}})

\int \frac{1}{x ^{3}} 1 - \frac{1}{x ^{2}} d x

What is the solution for y^'+(2-x/(x-1))y=0 ?
The solution for y^'+(2-x/(x-1))y=0 is y=e^{-x-1+c_{1}}x-e^{-x-1+c_{1}}