What is laplacetransform 5sin(2t) ?

The answer to laplacetransform 5sin(2t) is (10)/(s^2+4)

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laplacetransform 5sin(2t)

laplace transform

5 sin (2 t)

\frac{10}{s ^{2} + 4}

Solution steps

L {5 sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= 5 \cdot \frac{2}{s ^{2} + 4}

Refine

5 \frac{2}{s ^{2} + 4} : \frac{10}{s ^{2} + 4}

= \frac{10}{s ^{2} + 4}

s + 6

\frac{d}{d x} (\frac{1}{4 x})

\int_{1}^{2} e^{x^{2}} d x

\int_{1}^{3} x arctan (x) d x

x \to - 2 lim (- x^{2} + 7 x - 5)

What is laplacetransform 5sin(2t) ?
The answer to laplacetransform 5sin(2t) is (10)/(s^2+4)