What is the integral from 1 to 2 of e^{x^2} ?

The integral from 1 to 2 of e^{x^2} is (sqrt(pi)\erfi(2)-sqrt(pi)\erfi(1))/2

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integral from 1 to 2 of e^{x^2}

\int_{1}^{2} e^{x^{2}} d x

\frac{π erfi ( 2 ) - π erfi ( 1 )}{2}

Solution steps

\int_{1}^{2} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{1}^{2}

Compute the boundaries:

\frac{π erfi ( 2 ) - π erfi ( 1 )}{2}

= \frac{π erfi ( 2 ) - π erfi ( 1 )}{2}

\int_{1}^{3} x arctan (x) d x

x \to - 2 lim (- x^{2} + 7 x - 5)

\int e^{- 2 x} cos (2 x) d x

\frac{d y}{d x} + 2 x y = 4

\frac{d}{d x} (ln (13 - x^{2}))

What is the integral from 1 to 2 of e^{x^2} ?
The integral from 1 to 2 of e^{x^2} is (sqrt(pi)\erfi(2)-sqrt(pi)\erfi(1))/2