What is the derivative of 2^xsec(x) ?

The derivative of 2^xsec(x) is 2^xln(2)sec(x)+sec(x)tan(x)*2^x

What is the first derivative of 2^xsec(x) ?

The first derivative of 2^xsec(x) is 2^xln(2)sec(x)+sec(x)tan(x)*2^x

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\frac{d}{d x} (2^{x} sec (x))

2^{x} ln (2) sec (x) + sec (x) tan (x) \cdot 2^{x}

Solution steps

\frac{d}{d x} (2^{x} sec (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 2^{x}, g = sec (x)

= \frac{d}{d x} (2^{x}) sec (x) + \frac{d}{d x} (sec (x)) 2^{x}

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (sec (x)) = sec (x) tan (x)

= 2^{x} ln (2) sec (x) + sec (x) tan (x) \cdot 2^{x}

\frac{d y}{d x} + y^{9} x + 2 y = 0

\int (x^{3} - 3 x^{2} - x + 3) d x

y^{^{''}} - 5 y^{^{'}} + 6 y = 2 e t

\int_{0}^{1} x^{4} e^{3 x^{5}} d x

\frac{d}{d x} (\frac{4}{5 + cos ( x )})

What is the derivative of 2^xsec(x) ?
The derivative of 2^xsec(x) is 2^xln(2)sec(x)+sec(x)tan(x)*2^x
What is the first derivative of 2^xsec(x) ?
The first derivative of 2^xsec(x) is 2^xln(2)sec(x)+sec(x)tan(x)*2^x