What is (\partial)/(\partial x)(3x^2+6y) ?

The answer to (\partial)/(\partial x)(3x^2+6y) is 6x

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(\partial)/(\partial x)(3x^2+6y)

\frac{\partial}{\partial x} (3 x^{2} + 6 y)

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 6 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (6 y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (6 y) = 0

= 6 x + 0

Simplify

= 6 x

\frac{d}{d x} (- 0.5 x^{2})

g (x) = x^{5} + \frac{1}{x ^{5}}

x \to - 3 + lim (\frac{1}{x ^{2} - 9})

(1, - 19), (- 2, - 7)

\int (t ln (t))^{2} d t

What is (\partial)/(\partial x)(3x^2+6y) ?
The answer to (\partial)/(\partial x)(3x^2+6y) is 6x