What is the sum from n=1 to infinity of n^3*2^{-n} ?

The sum from n=1 to infinity of n^3*2^{-n} is converges

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sum from n=1 to infinity of n^3*2^{-n}

n = 1 \sum \infty n^{3} \cdot 2^{- n}

converges

Solution steps

n = 1 \sum \infty n^{3} \cdot 2^{- n}

Apply Series Ratio Test:

converges

= converges

\frac{d y}{d t} = y + \frac{3}{y ^{2}}

(\frac{x ^{2} + 2}{x ^{2} - 2})^{4}

\frac{1}{( 3 x + 1 )}

y = sin (x), y = cos (x)

(e^{, at})

What is the sum from n=1 to infinity of n^3*2^{-n} ?
The sum from n=1 to infinity of n^3*2^{-n} is converges