What is the solution for ((7y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 ?

The solution for ((7y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 is

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((7y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0

(\frac{7 y ^{2} - t ^{2}}{y ^{5}}) \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

Solution steps

(\frac{7 y ^{2} - t ^{2}}{y ^{5}}) \frac{d y}{d t} + \frac{t}{2 y ^{4}} = 0

Solve exact ODE:

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

y = \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{- 7 + 2 c _{1} t ^{2} + 49}{2 c _{1}}, y = - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}, y = - - \frac{2 c _{1} t ^{2} + 49 + 7}{2 c _{1}}

\int \frac{x ^{2} - 9}{x ^{2}} d x

y^{^{''}} - (\frac{6}{x}) y^{^{'}} - (\frac{4}{x ^{2}}) y = 0

\frac{d}{d a} (\frac{π ( 9 a ^{2} + 6 a + 1 )}{36 a})

n = 0 \sum \infty 1.0 5^{n}

\frac{d}{d x} (π sin (π x))

What is the solution for ((7y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 ?
The solution for ((7y^2-t^2)/(y^5))(dy)/(dt)+t/(2y^4)=0 is