What is the solution for y^{''}-(6/x)y^'-(4/(x^2))y=0 ?

The solution for y^{''}-(6/x)y^'-(4/(x^2))y=0 is y=c_{1}x^{(7+sqrt(65))/2}+c_{2}x^{(7-sqrt(65))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-(6/x)y^'-(4/(x^2))y=0

y^{^{''}} - (\frac{6}{x}) y^{^{'}} - (\frac{4}{x ^{2}}) y = 0

y = c_{1} x^{\frac{7 + 65}{2}} + c_{2} x^{\frac{7 - 65}{2}}

Solution steps

y^{''} (x) - (\frac{6}{x}) y^{'} (x) - (\frac{4}{x ^{2}}) y = 0

Solve linear ODE:

y = c_{1} x^{\frac{7 + 65}{2}} + c_{2} x^{\frac{7 - 65}{2}}

y = c_{1} x^{\frac{7 + 65}{2}} + c_{2} x^{\frac{7 - 65}{2}}

\frac{d}{d a} (\frac{π ( 9 a ^{2} + 6 a + 1 )}{36 a})

n = 0 \sum \infty 1.0 5^{n}

\frac{d}{d x} (π sin (π x))

\frac{0.26 s}{( s + 1 )}

16 - x, x + 4, 0, - 9

What is the solution for y^{''}-(6/x)y^'-(4/(x^2))y=0 ?
The solution for y^{''}-(6/x)y^'-(4/(x^2))y=0 is y=c_{1}x^{(7+sqrt(65))/2}+c_{2}x^{(7-sqrt(65))/2}