What is area sqrt(16-x),x+4,0,-9 ?

The answer to area sqrt(16-x),x+4,0,-9 is 271/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area sqrt(16-x),x+4,0,-9

area

16 - x, x + 4, 0, - 9

\frac{271}{6}

Decimal Notation

45.16666 \dots

Solution steps

Apply the area formula:

\int_{- 9}^{0} 16 - x - (x + 4) d x

Solve

\int_{- 9}^{0} 16 - x - (x + 4) d x : \frac{271}{6}

The area is:

= \frac{271}{6}

y = (sin (x)) (cos (x))

\int e^{- 2 x + 1} d x

\frac{\partial}{\partial x} (- 3 x y (- 9 - x - y))

\int 3 e^{- x} d x

n = 1 \sum \infty n^{2} \cdot e^{- n^{3}}

What is area sqrt(16-x),x+4,0,-9 ?
The answer to area sqrt(16-x),x+4,0,-9 is 271/6