What is the solution for y^'=(cos^2(t))(cos^2(2y)) ?

The solution for y^'=(cos^2(t))(cos^2(2y)) is y=(arctan(t+1/2 sin(2t)+c_{1}))/2+(pin)/2

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y^'=(cos^2(t))(cos^2(2y))

y^{^{'}} = (cos^{2} (t)) (cos^{2} (2 y))

y = \frac{arctan ( t + \frac{1}{2} sin ( 2 t ) + c _{1} )}{2} + \frac{πn}{2}

Solution steps

y^{'} (t) = (cos^{2} (t)) (cos^{2} (2 y))

Solve separable ODE:

y = \frac{arctan ( t + \frac{1}{2} sin ( 2 t ) + c _{1} )}{2} + \frac{πn}{2}

y = \frac{arctan ( t + \frac{1}{2} sin ( 2 t ) + c _{1} )}{2} + \frac{πn}{2}

(\frac{y ^{3}}{3}) + \frac{1}{4 y}

f (x) = \frac{x \cdot , ( x )}{1 + x}

x \to - 1 lim (x^{2} - 1)

f (x) = (3 x + 4) (5 - x^{2}) (4 + x^{2})

What is the solution for y^'=(cos^2(t))(cos^2(2y)) ?
The solution for y^'=(cos^2(t))(cos^2(2y)) is y=(arctan(t+1/2 sin(2t)+c_{1}))/2+(pin)/2