What is the limit as x approaches 3 of ((x^2-6))/((x-9)) ?

The limit as x approaches 3 of ((x^2-6))/((x-9)) is -1/2

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limit as x approaches 3 of ((x^2-6))/((x-9))

x \to 3 lim (\frac{( x ^{2} - 6 )}{( x - 9 )})

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

x \to 3 lim (\frac{x ^{2} - 6}{x - 9})

Plug in the value

x = 3

= \frac{3 ^{2} - 6}{3 - 9}

Simplify

\frac{3 ^{2} - 6}{3 - 9} : - \frac{1}{2}

= - \frac{1}{2}

\frac{d}{d x} (lo g_{6} (3 x^{3} + 4 x^{2} + 4 x))

\int 64 - 5 x^{2} d x

\int \frac{( x ^{2} )}{20 - 4 x + x ^{2}} d x

\int \frac{ln ( 16 x )}{x} d x

y^{^{'}} = \frac{e ^{t}}{2 y}

What is the limit as x approaches 3 of ((x^2-6))/((x-9)) ?
The limit as x approaches 3 of ((x^2-6))/((x-9)) is -1/2