What is the derivative of (2x)/(x+1) ?

The derivative of (2x)/(x+1) is 2/((x+1)^2)

What is the first derivative of (2x)/(x+1) ?

The first derivative of (2x)/(x+1) is 2/((x+1)^2)

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derivative of

\frac{2 x}{x + 1}

\frac{2}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 1) = 1

= 2 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{2}{( x + 1 ) ^{2}}

= \frac{2}{( x + 1 ) ^{2}}

\int \frac{1}{e ^{- 2 y}} d y

\int_{0}^{\frac{1}{2}} 30 x d x

\frac{d}{d x} (\frac{x + 1}{x ^{2} + 1})

\int \frac{1}{4} x^{4} d x

\frac{d}{d x} (e^{- 2 x} - 2 e^{- 2 x} x)

What is the derivative of (2x)/(x+1) ?
The derivative of (2x)/(x+1) is 2/((x+1)^2)
What is the first derivative of (2x)/(x+1) ?
The first derivative of (2x)/(x+1) is 2/((x+1)^2)