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Popular >

integral of 1/4 x^4

Solution

\int \frac{1}{4} x^{4} d x

Solution

\frac{x ^{5}}{20} + C

Solution steps

\int \frac{1}{4} x^{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int x^{4} d x

Apply the Power Rule

: \frac{x ^{5}}{5}

= \frac{1}{4} \cdot \frac{x ^{5}}{5}

Simplify

\frac{1}{4} \cdot \frac{x ^{5}}{5} : \frac{x ^{5}}{20}

= \frac{x ^{5}}{20}

Add a constant to the solution

= \frac{x ^{5}}{20} + C

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\int_{0}^{1} 4 x - 4 x d x

integral of (x^5)/((3-x^6)^4)

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{4}} d x

y^{''}+7y^'+12y=0

y^{^{''}} + 7 y^{^{'}} + 12 y = 0

Frequently Asked Questions (FAQ)

What is the integral of 1/4 x^4 ?
The integral of 1/4 x^4 is (x^5)/(20)+C