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Popular >

d/(dt)(-1cos(t)+8sin(t))

Solution

\frac{d}{d t} (- 1 cos (t) + 8 sin (t))

Solution

sin (t) + 8 cos (t)

Solution steps

\frac{d}{d t} (- 1 \cdot cos (t) + 8 sin (t))

Simplify

- 1 \cdot cos (t) + 8 sin (t) : - cos (t) + 8 sin (t)

= \frac{d}{d t} (- cos (t) + 8 sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (cos (t)) + \frac{d}{d t} (8 sin (t))

\frac{d}{d t} (cos (t)) = - sin (t)

\frac{d}{d t} (8 sin (t)) = 8 cos (t)

= - (- sin (t)) + 8 cos (t)

Simplify

= sin (t) + 8 cos (t)

Popular Examples

integral from 0 to 1 of 4sqrt(x)-4x

\int_{0}^{1} 4 x - 4 x d x

integral of (x^5)/((3-x^6)^4)

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{4}} d x

y^{''}+7y^'+12y=0

y^{^{''}} + 7 y^{^{'}} + 12 y = 0

sum from n=5 to infinity of (n!)/(n^n)

n = 5 \sum \infty \frac{n !}{n ^{n}}

integral of 1/(sqrt(-t^2+6t-8))

\int \frac{1}{- t ^{2} + 6 t - 8} d t

Frequently Asked Questions (FAQ)

What is the d/(dt)(-1cos(t)+8sin(t)) ?
The d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)
What is the first d/(dt)(-1cos(t)+8sin(t)) ?
The first d/(dt)(-1cos(t)+8sin(t)) is sin(t)+8cos(t)