What is the integral of (x^5)/((3-x^6)^4) ?

The integral of (x^5)/((3-x^6)^4) is 1/(18(3-x^6)^3)+C

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integral of (x^5)/((3-x^6)^4)

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{4}} d x

\frac{1}{18 ( 3 - x ^{6} ) ^{3}} + C

Solution steps

\int \frac{x ^{5}}{( 3 - x ^{6} ) ^{4}} d x

Apply u-substitution

: \int - \frac{1}{6 u ^{4}} d u

= \int - \frac{1}{6 u ^{4}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{6} \cdot \int \frac{1}{u ^{4}} d u

Apply the Power Rule

: - \frac{1}{3 u ^{3}}

= - \frac{1}{6} (- \frac{1}{3 u ^{3}})

Substitute back

u = 3 - x^{6}

= - \frac{1}{6} (- \frac{1}{3 ( 3 - x ^{6} ) ^{3}})

Simplify

- \frac{1}{6} (- \frac{1}{3 ( 3 - x ^{6} ) ^{3}}) : \frac{1}{18 ( 3 - x ^{6} ) ^{3}}

= \frac{1}{18 ( 3 - x ^{6} ) ^{3}}

Add a constant to the solution

= \frac{1}{18 ( 3 - x ^{6} ) ^{3}} + C

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\int \frac{1}{- t ^{2} + 6 t - 8} d t

\frac{d}{d x} (0.006 x^{3} + 0.02 x^{2} + 0.5 x)

\frac{d}{d y} (y cos (x) y)

What is the integral of (x^5)/((3-x^6)^4) ?
The integral of (x^5)/((3-x^6)^4) is 1/(18(3-x^6)^3)+C