What is (\partial)/(\partial x)(1+ln(x)) ?

The answer to (\partial)/(\partial x)(1+ln(x)) is 1/x

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(\partial)/(\partial x)(1+ln(x))

\frac{\partial}{\partial x} (1 + ln (x))

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (1 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (ln (x))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

s (t) = \frac{t ^{2} + 40 t}{5}

\frac{\partial}{\partial x} (e^{(x^{2} - y^{2})})

(36 - x^{2}) \frac{d y}{d x} = 1

\int_{0}^{\frac{π}{3}} (tan (x))^{2} d x

\int 9 ln (x^{2} - 1) d x

What is (\partial)/(\partial x)(1+ln(x)) ?
The answer to (\partial)/(\partial x)(1+ln(x)) is 1/x