What is the integral from 0 to 15 of 24/25 piy^2 ?

The integral from 0 to 15 of 24/25 piy^2 is 1080pi

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integral from 0 to 15 of 24/25 piy^2

\int_{0}^{15} \frac{24}{25} π y^{2} d y

1080 π

Decimal Notation

3392.92006 \dots

Solution steps

\int_{0}^{15} \frac{24}{25} π y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{24}{25} π \cdot \int_{0}^{15} y^{2} d y

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{24 π}{25} \cdot \int_{0}^{15} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{15}

= \frac{24 π}{25} [\frac{y ^{3}}{3}]_{0}^{15}

Compute the boundaries:

1125

= \frac{24 π}{25} \cdot 1125

Simplify

= 1080 π

\frac{\partial}{\partial x} (2 sin (4 x))

\frac{d y}{d x} = (x)

x \to 0 lim (+ (x^{s i n (x)}))

y^{^{''}} + 18 y^{^{'}} + 82 y = 0

\int_{0}^{2} 2 π (y + 1) (1) d y

What is the integral from 0 to 15 of 24/25 piy^2 ?
The integral from 0 to 15 of 24/25 piy^2 is 1080pi