What is the integral from-1 to 3 of (5-1/4 x^3) ?

The integral from-1 to 3 of (5-1/4 x^3) is 15

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integral from-1 to 3 of (5-1/4 x^3)

\int_{- 1}^{3} (5 - \frac{1}{4} x^{3}) d x

15

Solution steps

\int_{- 1}^{3} 5 - \frac{1}{4} x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} 5 d x - \int_{- 1}^{3} \frac{1}{4} x^{3} d x

\int_{- 1}^{3} 5 d x = 20

\int_{- 1}^{3} \frac{1}{4} x^{3} d x = 5

= 20 - 5

Simplify

= 15

\int \frac{7 x ^{2}}{1 + x ^{6}} d x

(x^{2} y^{2} - x^{4}) y^{^{'}} = x^{2} y^{2} - y^{4}

x \to - 1 lim (ln (1 + x))

\frac{d}{d x} (ln (4 x - 5))

\frac{1}{1 - x - x ^{2}}

What is the integral from-1 to 3 of (5-1/4 x^3) ?
The integral from-1 to 3 of (5-1/4 x^3) is 15