What is area 7e^x,7xe^{x^2},0,1 ?

The answer to area 7e^x,7xe^{x^2},0,1 is 7(e-1)-(7(e-1))/2

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area 7e^x,7xe^{x^2},0,1

area

7 e^{x}, 7 x e^{x^{2}}, 0, 1

7 (e - 1) - \frac{7 ( e - 1 )}{2}

Decimal Notation

6.01398 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x

Solve

\int_{0}^{1} 7 e^{x} - 7 x e^{x^{2}} d x : 7 (e - 1) - \frac{7 ( e - 1 )}{2}

The area is:

= 7 (e - 1) - \frac{7 ( e - 1 )}{2}

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What is area 7e^x,7xe^{x^2},0,1 ?
The answer to area 7e^x,7xe^{x^2},0,1 is 7(e-1)-(7(e-1))/2