What is the solution for x^2y^{''}+3xy^'-35y=0 ?

The solution for x^2y^{''}+3xy^'-35y=0 is y=c_{1}x^5+(c_{2})/(x^7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^{''}+3xy^'-35y=0

x^{2} y^{^{''}} + 3 x y^{^{'}} - 35 y = 0

y = c_{1} x^{5} + \frac{c _{2}}{x ^{7}}

Solution steps

x^{2} y^{''} (x) + 3 x y^{'} (x) - 35 y = 0

Solve linear ODE:

y = c_{1} x^{5} + \frac{c _{2}}{x ^{7}}

y = c_{1} x^{5} + \frac{c _{2}}{x ^{7}}

\int tan (x) (4 cos (x) + 8 sec (x)) d x

\int \frac{8 x}{1 + x ^{2}} d x

\frac{d y}{d x} + y^{5} x + 6 y = 0

\int \frac{1}{x ^{2} 4 - x ^{2}} d x

\frac{d}{d x} (3 x e^{x} - cos (x))

What is the solution for x^2y^{''}+3xy^'-35y=0 ?
The solution for x^2y^{''}+3xy^'-35y=0 is y=c_{1}x^5+(c_{2})/(x^7)