What is the derivative of (x^4-3x^2) ?

The derivative of (x^4-3x^2) is 2(x^4-3x)(4x^3-3)

What is the first derivative of (x^4-3x^2) ?

The first derivative of (x^4-3x^2) is 2(x^4-3x)(4x^3-3)

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\frac{d}{d x} ((x^{4} - 3 x)^{2})

2 (x^{4} - 3 x) (4 x^{3} - 3)

Solution steps

\frac{d}{d x} ((x^{4} - 3 x)^{2})

Apply the chain rule:

2 (x^{4} - 3 x) \frac{d}{d x} (x^{4} - 3 x)

= 2 (x^{4} - 3 x) \frac{d}{d x} (x^{4} - 3 x)

\frac{d}{d x} (x^{4} - 3 x) = 4 x^{3} - 3

= 2 (x^{4} - 3 x) (4 x^{3} - 3)

x^{2} y^{^{''}} + 2 x y^{^{'}} - 2 y = x^{2} ln (x)

\frac{1}{4} \cdot sin (2 t)

\frac{d}{d x} (\frac{e ^{x} x - e ^{x}}{7 x ^{2}})

\frac{\partial}{\partial y} (sin (x - y) + (x - y))

\frac{d}{d x} (x - 3 e^{x})

What is the derivative of (x^4-3x^2) ?
The derivative of (x^4-3x^2) is 2(x^4-3x)(4x^3-3)
What is the first derivative of (x^4-3x^2) ?
The first derivative of (x^4-3x^2) is 2(x^4-3x)(4x^3-3)