What is taylor 3/(1+3x) ?

The answer to taylor 3/(1+3x) is 3-9x+27x^2-81x^3+243x^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor 3/(1+3x)

taylor

\frac{3}{1 + 3 x}

3 - 9 x + 27 x^{2} - 81 x^{3} + 243 x^{4} + \dots

Solution steps

Apply the Taylor Formula

= 3 + \frac{\frac{d}{d x} ( \frac{3}{1 + 3 x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{3}{1 + 3 x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{3}{1 + 3 x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 3 + \frac{- 9}{1 !} x + \frac{54}{2 !} x^{2} + \frac{- 486}{3 !} x^{3} + \frac{5832}{4 !} x^{4} + \dots

Refine

= 3 - 9 x + 27 x^{2} - 81 x^{3} + 243 x^{4} + \dots

\int x 5 + 2 x d x

\frac{d}{d x} (2 sin (x) - cos (2 x))

y^{^{''}} - 4 y^{^{'}} + 3 y = 10 e^{3 t}

\frac{d y}{d x} = \frac{sin ( x )}{cos ( y )}

\int_{0}^{\infty} (e^{- x}) d x

What is taylor 3/(1+3x) ?
The answer to taylor 3/(1+3x) is 3-9x+27x^2-81x^3+243x^4+\ldots