What is the derivative of (-4x/((x^2-1)^2)) ?

The derivative of (-4x/((x^2-1)^2)) is -(4(-3x^2-1))/((x^2-1)^3)

What is the first derivative of (-4x/((x^2-1)^2)) ?

The first derivative of (-4x/((x^2-1)^2)) is -(4(-3x^2-1))/((x^2-1)^3)

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\frac{d}{d x} (\frac{- 4 x}{( x ^{2} - 1 ) ^{2}})

- \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 4 x}{( x ^{2} - 1 ) ^{2}})

Simplify

\frac{- 4 x}{( x ^{2} - 1 ) ^{2}} : - \frac{4 x}{( x ^{2} - 1 ) ^{2}}

= \frac{d}{d x} (- \frac{4 x}{( x ^{2} - 1 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{x}{( x ^{2} - 1 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 4 \cdot \frac{\frac{d x}{d x} ( x ^{2} - 1 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 1 ) ^{2} ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} - 1)^{2}) = 4 x (x^{2} - 1)

= - 4 \cdot \frac{1 \cdot ( x ^{2} - 1 ) ^{2} - 4 x ( x ^{2} - 1 ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}}

Simplify

- 4 \cdot \frac{1 \cdot ( x ^{2} - 1 ) ^{2} - 4 x ( x ^{2} - 1 ) x}{( ( x ^{2} - 1 ) ^{2} ) ^{2}} : - \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

= - \frac{4 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

\int 2 e^{9 x} d x

\frac{\partial}{\partial y} (\frac{2 x ^{2} y}{4 + x ^{2} y ^{2}})

\int sec^{2} (2 θ) d θ

\frac{\partial}{\partial z} (9 x sin (y - z))

y^{^{''}} + y^{^{'}} - 3 y = 6 sin (2 x)

What is the derivative of (-4x/((x^2-1)^2)) ?
The derivative of (-4x/((x^2-1)^2)) is -(4(-3x^2-1))/((x^2-1)^3)
What is the first derivative of (-4x/((x^2-1)^2)) ?
The first derivative of (-4x/((x^2-1)^2)) is -(4(-3x^2-1))/((x^2-1)^3)