What is (\partial)/(\partial x)(e^x+xcos(y)) ?

The answer to (\partial)/(\partial x)(e^x+xcos(y)) is e^x+cos(y)

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(\partial)/(\partial x)(e^x+xcos(y))

\frac{\partial}{\partial x} (e^{x} + x cos (y))

e^{x} + cos (y)

Solution steps

\frac{\partial}{\partial x} (e^{x} + x cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (x cos (y))

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

= e^{x} + cos (y)

\int \frac{x ^{2} - 1}{e ^{\frac{x}{2}}} d x

\frac{d}{d x} (3^{x - in x})

\int \frac{x ^{2}}{49 + x ^{2}} d x

x \to 0 lim (2 x)

\frac{d}{d x} (2 x^{2} + 4 x)

What is (\partial)/(\partial x)(e^x+xcos(y)) ?
The answer to (\partial)/(\partial x)(e^x+xcos(y)) is e^x+cos(y)