What is the integral from-2 to 14 of 1/((x+2)^{1/4)} ?

The integral from-2 to 14 of 1/((x+2)^{1/4)} is 32/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 14 of 1/((x+2)^{1/4)}

\int_{- 2}^{14} \frac{1}{( x + 2 ) ^{\frac{1}{4}}} d x

\frac{32}{3}

Decimal Notation

10.66666 \dots

Solution steps

\int_{- 2}^{14} \frac{1}{( x + 2 ) ^{\frac{1}{4}}} d x

Apply u-substitution

: \int_{0}^{16} \frac{1}{u ^{\frac{1}{4}}} d u

= \int_{0}^{16} \frac{1}{u ^{\frac{1}{4}}} d u

Apply the Power Rule

: [\frac{4}{3} u^{\frac{3}{4}}]_{0}^{16}

= [\frac{4}{3} u^{\frac{3}{4}}]_{0}^{16}

Compute the boundaries:

\frac{32}{3}

= \frac{32}{3}

\int \frac{x ^{3}}{x} d x

\int x + 2 - x^{2} d x

y^{^{'}} = 9 x + y, y (0) = 4

\int_{0}^{1} \frac{13}{4 y - 1} d y

What is the integral from-2 to 14 of 1/((x+2)^{1/4)} ?
The integral from-2 to 14 of 1/((x+2)^{1/4)} is 32/3