What is laplacetransform 4e^{-3t+2} ?

The answer to laplacetransform 4e^{-3t+2} is (4e^2)/(s+3)

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laplacetransform 4e^{-3t+2}

laplace transform

4 e^{- 3 t + 2}

\frac{4 e ^{2}}{s + 3}

Solution steps

L {4 e^{- 3 t + 2}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 e^{2} L {e^{- 3 t}}

L {e^{- 3 t}} : \frac{1}{s + 3}

= 4 e^{2} \frac{1}{s + 3}

Refine

4 e^{2} \frac{1}{s + 3} : \frac{4 e ^{2}}{s + 3}

= \frac{4 e ^{2}}{s + 3}

x \to \infty lim (- \frac{4}{x})

\int \frac{e ^{x}}{2 x} d x

x \to - 1 lim (6)

8 f - g, at g (2)

\int_{5}^{10} 100 - x^{2} d x

What is laplacetransform 4e^{-3t+2} ?
The answer to laplacetransform 4e^{-3t+2} is (4e^2)/(s+3)