What is the derivative of 8f-g,\at g(2) ?

The derivative of 8f-g,\at g(2) is 8

What is the first derivative of 8f-g,\at g(2) ?

The first derivative of 8f-g,\at g(2) is 8

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derivative of

8 f - g, at g (2)

8

Solution steps

\frac{d}{df} (8 f - g)

Treat

g

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{df} (8 f) - \frac{d g}{df}

\frac{d}{df} (8 f) = 8

\frac{d g}{df} = 0

= 8 - 0

Simplify

= 8

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What is the derivative of 8f-g,\at g(2) ?
The derivative of 8f-g,\at g(2) is 8
What is the first derivative of 8f-g,\at g(2) ?
The first derivative of 8f-g,\at g(2) is 8