What is the derivative of 1/8 x^2-7x+16 ?

The derivative of 1/8 x^2-7x+16 is x/4-7

What is the first derivative of 1/8 x^2-7x+16 ?

The first derivative of 1/8 x^2-7x+16 is x/4-7

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derivative of

\frac{1}{8} x^{2} - 7 x + 16

\frac{x}{4} - 7

Solution steps

\frac{d}{d x} (\frac{1}{8} x^{2} - 7 x + 16)

Simplify

\frac{1}{8} x^{2} - 7 x + 16 : \frac{x ^{2}}{8} - 7 x + 16

= \frac{d}{d x} (\frac{x ^{2}}{8} - 7 x + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{8}) - \frac{d}{d x} (7 x) + \frac{d}{d x} (16)

\frac{d}{d x} (\frac{x ^{2}}{8}) = \frac{x}{4}

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (16) = 0

= \frac{x}{4} - 7 + 0

Simplify

= \frac{x}{4} - 7

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What is the derivative of 1/8 x^2-7x+16 ?
The derivative of 1/8 x^2-7x+16 is x/4-7
What is the first derivative of 1/8 x^2-7x+16 ?
The first derivative of 1/8 x^2-7x+16 is x/4-7