What is the first derivative of 6e^r ?

The first derivative of 6e^r is 6e^r

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derivative of 6e^r

derivative of

6 e^{r}

6 e^{r}

Solution steps

\frac{d}{d r} (6 e^{r})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d r} (e^{r})

Apply the common derivative:

\frac{d}{d r} (e^{r}) = e^{r}

= 6 e^{r}

\int_{1}^{2} \frac{ln ( x ^{7} )}{x} d x

3 e^{3 x} cos (2 x) - 2 e^{3 x} sin (2 x)

- 4.9 t^{2} + 25 t + 3

\int_{- 2}^{2} 2 + ∣ x ∣ d x

x^{2} (580 - \frac{x}{3})