What is the derivative of-4.9t^2+25t+3 ?

The derivative of-4.9t^2+25t+3 is -9.8t+25

What is the first derivative of-4.9t^2+25t+3 ?

The first derivative of-4.9t^2+25t+3 is -9.8t+25

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derivative of

- 4.9 t^{2} + 25 t + 3

- 9.8 t + 25

Solution steps

\frac{d}{d t} (- 4.9 t^{2} + 25 t + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (4.9 t^{2}) + \frac{d}{d t} (25 t) + \frac{d}{d t} (3)

\frac{d}{d t} (4.9 t^{2}) = 9.8 t

\frac{d}{d t} (25 t) = 25

\frac{d}{d t} (3) = 0

= - 9.8 t + 25 + 0

Simplify

= - 9.8 t + 25

\int_{- 2}^{2} 2 + ∣ x ∣ d x

x^{2} (580 - \frac{x}{3})

9.8 - \frac{y}{5}

y^{^{''}} + 4 y^{^{'}} + 4 = 0

\int cos^{9} (x) tan^{8} (x) d x

What is the derivative of-4.9t^2+25t+3 ?
The derivative of-4.9t^2+25t+3 is -9.8t+25
What is the first derivative of-4.9t^2+25t+3 ?
The first derivative of-4.9t^2+25t+3 is -9.8t+25