What is area (1/(14x^2)),x,(x/4) ?

The answer to area (1/(14x^2)),x,(x/4) is (6\sqrt[3]{14}-3*2^{2/3}\sqrt[3]{7})/(56)

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area (1/(14x^2)),x,(x/4)

area

(\frac{1}{14 x ^{2}}), x, (\frac{x}{4})

Decimal Notation

0.09555 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = (\frac{x}{4}) : x = 0

Simplify

90 x

\frac{\partial}{\partial y} (- y sin (x))

\int_{- 2}^{2} \frac{3}{2} x^{2} d x

x \to 1 lim (- x^{2} + 4 x)

x \to 2 + lim (\frac{x ^{2} - 2 x - 8}{x ^{2} - 5 x + 6})

What is area (1/(14x^2)),x,(x/4) ?
The answer to area (1/(14x^2)),x,(x/4) is (6\sqrt[3]{14}-3*2^{2/3}\sqrt[3]{7})/(56)