What is (\partial)/(\partial y)(-ysin(x)) ?

The answer to (\partial)/(\partial y)(-ysin(x)) is -sin(x)

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(\partial)/(\partial y)(-ysin(x))

\frac{\partial}{\partial y} (- y sin (x))

- sin (x)

Solution steps

\frac{\partial}{\partial y} (- y sin (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - sin (x) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - sin (x) \cdot 1

Simplify

= - sin (x)

\int_{- 2}^{2} \frac{3}{2} x^{2} d x

x \to 1 lim (- x^{2} + 4 x)

x \to 2 + lim (\frac{x ^{2} - 2 x - 8}{x ^{2} - 5 x + 6})

\int \frac{x + 4}{x ^{2} + 8 x + 17} d x

\frac{d}{d x} (2 + \frac{1}{x})

What is (\partial)/(\partial y)(-ysin(x)) ?
The answer to (\partial)/(\partial y)(-ysin(x)) is -sin(x)