What is the derivative of 2+1/x ?

The derivative of 2+1/x is -1/(x^2)

What is the first derivative of 2+1/x ?

The first derivative of 2+1/x is -1/(x^2)

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\frac{d}{d x} (2 + \frac{1}{x})

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (2 + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 0 - \frac{1}{x ^{2}}

Simplify

= - \frac{1}{x ^{2}}

f (x) = x (x + 1)^{2}

\frac{\partial}{\partial x} (2 x^{2} + 3 y^{2} - z^{2})

y = 4 + x x, (1, 5)

x \to 2 lim (x^{4} - 8)

y^{^{''}} + y^{^{'}} - 6 y = 12 x - 50 sin (x)

What is the derivative of 2+1/x ?
The derivative of 2+1/x is -1/(x^2)
What is the first derivative of 2+1/x ?
The first derivative of 2+1/x is -1/(x^2)